Circular Motion example 2

The video tutorial explains how to calculate the acceleration vector of a car on a circular racetrack. Starting from rest, the car reaches a speed of 200 km/h at the finish line. The tutorial covers defining variables, setting initial conditions, and deriving both tangential and normal acceleration components. It concludes with expressing the acceleration vector in Cartesian coordinates.

What is the initial speed of the car as it starts on the circular racetrack?

• 0 km/h

• 100 km/h

• 50 km/h

• 200 km/h

What is the curved distance X when the car completes a full lap on the track?

• R

• 2πR

• πR

• 4πR

As the car crosses the finish line, in which direction is its velocity vector pointing?

• Perpendicular to the path

• Tangential to the path

• Towards the center of the circle

• Opposite to the direction of motion

What is the formula for the tangential component of acceleration (aT) in terms of speed (V) and distance (X)?

• aT = V^2 / X

• aT = dV/dX * V

• aT = V^2 / R

• aT = dV/dt

How is the normal component of acceleration (an) calculated for circular motion?

• an = V^2 / X

• an = V^2 / R

• an = dV/dt

• an = R^2 / V

What is the value of the tangential acceleration component (aT) when the car's speed is 55.56 m/s?

• 10.123 m/s²

• 5.678 m/s²

• 30.87 m/s²

• 2.456 m/s²

In Cartesian coordinates, how is the acceleration vector expressed?

• 2.456i - 30.87j

• -30.87i + 2.456j

• 30.87i + 2.456j

• -2.456i + 30.87j