Dividing two polynomials using synthetic division

Dividing two polynomials using synthetic division

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

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The video tutorial explains how to solve a polynomial using synthetic division. It begins by ensuring the divisor is a linear binomial and setting it equal to zero. The process involves setting up a division box, listing coefficients, and performing calculations to find the remainder and quotient. The tutorial concludes by interpreting the results and correcting any misunderstandings about the quotient.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in synthetic division when dealing with a linear binomial divisor?

Set the divisor equal to zero

Divide the terms directly

Add the coefficients

Multiply the coefficients

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When setting up the synthetic division box, what should you do if a term is missing in the polynomial?

Include a zero for the missing term

Subtract one from the missing term

Ignore the missing term

Add one to the missing term

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In synthetic division, what is the first number you bring down from the coefficients?

The first coefficient

The coefficient of the constant term

The middle coefficient

The last coefficient

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the last term in the synthetic division process represent?

The remainder

The constant term

The divisor

The quotient

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After performing synthetic division, what is the relationship between the divisor and the polynomial?

The divisor divides the polynomial evenly

The divisor is the quotient

The divisor is unrelated to the polynomial

The divisor is the remainder