Evaluate the Composition of a Rational and Radical Function

The video tutorial explains the process of evaluating the composition of functions, specifically J of H of -, 3. It begins by introducing the functions JX and H of X, and then demonstrates how to calculate H of -, 3 by plugging in values. The tutorial further simplifies the expression and verifies the result, ensuring a clear understanding of the mathematical process involved.

What is the function J(X) as described in the video?

• J(X) = X + 2

• J(X) = 2X + 1

• J(X) = 1/(X + 3)

• J(X) = X - 3

What is the result of H(-3) when calculated?

• H(-3) = -1

• H(-3) = 1

• H(-3) = 0

• H(-3) = 2

What is the value of H(X) as given in the video?

• H(X) = X - 2

• H(X) = 1/(X + 3)

• H(X) = X + 2

• H(X) = 2X + 1

After substituting H(-3) into J(X), what is the final result of the composition?

• 2

• 0

• 1

• -1

What is the process described for finding the composition of functions?

• Dividing the functions

• Adding the functions together

• Substituting one function into another

• Multiplying the functions