Solving trigonometric equation by using reciprocal function

The video tutorial explains how to solve for X within the interval of 0 to 2π by isolating the cosecant function and using the unit circle. It covers the relationship between trigonometric functions and their reciprocals, focusing on finding when the sine value equals sqrt 3/2. The tutorial concludes with a discussion on interval restrictions and potential variations in problem conditions.

What is the first step in solving for X within the range of 0 to 2π?

• Subtract two from both sides

• Evaluate the sine function

• Isolate the cosine function

• Multiply by sqrt 3

How is the cosecant function related to the sine function?

• Cosecant is the square of sine

• Cosecant is the reciprocal of sine

• Cosecant is the inverse of cosine

• Cosecant is the tangent of sine

What does the cosine of an angle on the unit circle represent?

• The cosecant of the angle

• The tangent of the angle

• The Y coordinate of the point

• The X coordinate of the point

Which values of X satisfy the condition where the sine value equals sqrt 3 / 2?

• X = π/6 and 5π/6

• X = π/3 and 2π/3

• X = π/4 and 3π/4

• X = π/2 and 3π/2

Why are only certain points on the unit circle considered for solutions?

• Because they are in the first quadrant

• Because they are within the interval of 0 to 2π

• Because they have positive sine values

• Because they are in the second quadrant