Crystal Lattice Structures: Density Calculation 4

The video tutorial explains how to calculate the density of potassium, which forms a body-centered cubic lattice. It covers the necessary formula, unit conversions, and step-by-step calculations, resulting in a density of 0.812 grams per cubic centimeter. The tutorial emphasizes the importance of using the correct formula and understanding unit conversions.

What is the structure of the lattice formed by potassium?

• Face-centered cubic

• Body-centered cubic

• Hexagonal close-packed

• Simple cubic

Which of the following is the correct formula for calculating the density of a body-centered cubic lattice?

• Density = (2 atoms * atomic mass) / (Avogadro's number * volume)

• Density = (4 atoms * atomic mass) / (Avogadro's number * volume)

• Density = (3 atoms * atomic mass) / (Avogadro's number * volume)

• Density = (atomic mass) / (Avogadro's number * volume)

What is the conversion factor from angstroms to centimeters used in the calculation?

• 1 Angstrom = 10^-9 centimeters

• 1 Angstrom = 10^-7 centimeters

• 1 Angstrom = 10^-8 centimeters

• 1 Angstrom = 10^-10 centimeters

What is the calculated density of potassium in grams per cubic centimeter?

• 0.712

• 0.912

• 1.012

• 0.812

Why is potassium expected to have a low density?

• Because it is an alkali metal

• Because it has a high atomic mass

• Because it forms a face-centered cubic lattice

• Because it is a transition metal