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Evaluating the composition of Functions using Right Triangles

Evaluating the composition of Functions using Right Triangles

Assessment

Interactive Video

Mathematics

11th Grade - University

Practice Problem

Hard

Created by

Wayground Content

FREE Resource

The video tutorial explains how to evaluate the cosecant of the arctan of X divided by the square root of 2. It begins by setting up the problem and noting the absence of a point on the unit circle, necessitating the creation of a triangle. The instructor explains how to find the inverse tangent and create a triangle in the appropriate quadrant. Using the Pythagorean theorem, the hypotenuse is calculated. Finally, the cosecant is determined by dividing the hypotenuse by the opposite side, resulting in the expression sqrt(X^2 + 2) / X.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in evaluating the cosecant of arctan of X divided by sqrt 2?

Directly calculate the cosecant

Find a point on the unit circle

Create a triangle

Use the sine function

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which quadrants are relevant when dealing with the arctangent function?

First and second

Second and third

First and fourth

Third and fourth

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you calculate the hypotenuse in the given problem?

Using the sine function

Using the cosine function

Using the Pythagorean theorem

Using the tangent function

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula for cosecant in terms of a triangle?

Hypotenuse over adjacent

Hypotenuse over opposite

Adjacent over hypotenuse

Opposite over hypotenuse

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final expression for the cosecant of arctan of X divided by sqrt 2?

sqrt(2) / X

X / sqrt(X^2 + 2)

sqrt(X^2 + 2) / X

X^2 + 2 / X

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