Dividing polynomials using synthetic division

The video tutorial explains how to perform synthetic division on a polynomial using a binomial divisor. It covers the setup process, including the use of placeholders for missing terms, and walks through the calculation steps. The tutorial concludes by interpreting the results, highlighting the quotient and remainder, and explaining how to express the final answer.

Why is it necessary to have a binomial divisor in synthetic division?

• Because synthetic division only works with binomials

• Because it simplifies the process

• Because it allows for easier multiplication

• Because it reduces the number of steps

What should you do if a polynomial term is missing during synthetic division?

• Use the next available term

• Ignore the missing term

• Include a zero as a placeholder

• Add a random coefficient

In synthetic division, what is the first step after writing down the coefficients?

• Multiply the first coefficient by the divisor

• Add the coefficients together

• Bring down the first coefficient

• Divide the first coefficient by the divisor

What does a non-zero remainder indicate in synthetic division?

• The divisor does not evenly divide the polynomial

• The division is incorrect

• The divisor is a factor of the polynomial

• The polynomial is incomplete

How is the final answer expressed in synthetic division when there is a remainder?

• As a product of the divisor and quotient

• As a remainder only

• As a quotient with the remainder over the divisor

• As a single polynomial