Find How Many Times Greater Using Scientific Notation

The video tutorial explains how to solve a standardized math test question comparing the speed of light and sound in cold air. It involves setting up an equation using scientific notation to determine how many times greater the speed of light is compared to sound. The solution involves dividing the factors and subtracting the exponents to find that the speed of light is 10^6 times the speed of sound.

What is the approximate speed of light in cold air as given in the video?

• 3 * 10^2 meters per second

• 3 * 10^4 meters per second

• 3 * 10^8 meters per second

• 3 * 10^6 meters per second

How is the speed of sound in cold air represented in scientific notation?

• 3 * 10^2 meters per second

• 3 * 10^4 meters per second

• 3 * 10^6 meters per second

• 3 * 10^8 meters per second

What operation is used to find how many times greater the speed of light is compared to the speed of sound?

• Addition

• Subtraction

• Division

• Multiplication

When dividing powers in scientific notation, what mathematical operation is performed on the exponents?

• Division

• Multiplication

• Subtraction

• Addition

What is the final result for how many times greater the speed of light is compared to the speed of sound?

• 1 * 10^4

• 1 * 10^5

• 1 * 10^6

• 1 * 10^7