Solving Systems of Equations by Elimination

Solving Systems of Equations by Elimination

Assessment

Interactive Video

Mathematics

1st - 6th Grade

Hard

Created by

Quizizz Content

FREE Resource

The video tutorial explains how to solve systems of linear equations using the elimination method, focusing on the use of multipliers to achieve opposite coefficients. It begins with an overview of systems of equations and their solutions, then introduces algebraic methods like substitution and elimination. The tutorial emphasizes the importance of multipliers in elimination and provides a detailed example problem to illustrate the process. By the end, viewers will understand how to solve systems algebraically by elimination when a multiplier is needed.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary goal when solving systems of equations using elimination?

To find the values of x and y using substitution

To estimate the solution using graphing

To simplify two equations into one equation with one variable

To find the point of intersection on a graph

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to have opposite coefficients in elimination?

To eliminate one variable when the equations are added

To make the equations easier to graph

To ensure the equations have the same solution

To simplify the process of substitution

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens when you multiply each term of an equation by the same number?

The solution to the equation changes

The equation becomes invalid

The equation remains true

The coefficients of the variables become zero

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example provided, what was the solution to the system of equations?

x = 5, y = 1

x = 0, y = 0

x = -9, y = 1

x = 1, y = -9

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of verifying the solution by graphing?

To check if the equations are linear

To find a different solution

To ensure the solution is an estimation

To confirm the point of intersection matches the algebraic solution