Introductory Newton's 2nd Law Example Problem and Demonstration

Introductory Newton's 2nd Law Example Problem and Demonstration

Assessment

Interactive Video

Physics, Science, Engineering

11th Grade - University

Hard

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The video tutorial demonstrates an example problem using Newton's second law to determine the force of friction between a dynamics cart and a track. The problem involves a cart with a force sensor, and the video guides through setting up the problem, converting units, drawing a free body diagram, and applying Newton's second law. The tutorial calculates acceleration using uniformly accelerated motion equations and solves for the force of friction, highlighting its negligible impact compared to the applied force.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total mass of the cart and force sensor used in the experiment?

813 grams

713 grams

613 grams

513 grams

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the average force applied to the cart measured?

By calculating the cart's displacement

With a force sensor attached to the cart

By observing the cart's speed

Using a spring scale

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial velocity of the cart when it is released?

1 m/s

0.5 m/s

1.5 m/s

0 m/s

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which force acts in the opposite direction to the cart's motion?

Gravitational force

Frictional force

Applied force

Normal force

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula used to calculate the force of friction in this experiment?

Force of friction = applied force - mass x acceleration

Force of friction = mass x acceleration

Force of friction = applied force + mass x acceleration

Force of friction = mass x velocity

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the calculated acceleration of the cart in the x direction?

0.786 m/s²

1.15 m/s²

2 m/s²

0.5 m/s²

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What percentage of the applied force is the force of friction approximately?

0.6%

1.6%

2.6%

3.6%