Describe an advanced data structure : Find the Given-Length Subarray with the Maximum Minimum
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Information Technology (IT), Architecture
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University
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Practice Problem
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Hard
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the main goal when finding the maximum minimum of a given length subarray?
To find the smallest element in the array
To find the largest element in the array
To find the subarray with the largest minimum value
To find the subarray with the smallest maximum value
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is a key characteristic of a deque data structure?
It is a last in, first out structure
It is a first in, first out structure
It allows insertion and removal only from one end
It allows insertion and removal from both ends
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why do we remove elements from the deque that are larger than the current element?
Because they are no longer needed for the maximum calculation
Because they cannot contribute to the minimum of the subarray
Because they are already part of another subarray
Because they are duplicates
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the main advantage of using a deque over a trivial O(N^2) solution?
It provides more accurate results
It uses less memory
It is easier to implement
It reduces the time complexity to O(N)
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What happens if the distance between the current element and the first element in the deque is larger than the given length?
The current element is added to the deque
The deque is reset
The first element in the deque is removed
The current element is ignored
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How does the deque help in maintaining the minimum of subarrays?
By storing the sum of elements
By storing indices of potential minimum elements
By storing only the maximum elements
By keeping all elements in sorted order
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the purpose of appending indices instead of elements to the deque?
To ensure the deque is always sorted
To simplify calculations for removing elements that are too far
To avoid duplicate elements
To save memory space
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