Projectile Motion: Solving another problem

The video tutorial explains how to determine the velocity needed for a second ball thrown at a 30-degree angle to reach the same height as a first ball thrown vertically. It involves analyzing the motion of the first ball, using motion equations, and calculating the necessary velocity for the second ball by ensuring the Y component of its velocity matches that of the first ball.

What is the main goal when throwing the second ball at a 30-degree angle?

• To make it travel the longest distance

• To make it reach the same height as the first ball

• To make it spin the most

• To make it return in the shortest time

How long does it take for the first ball to reach the top of its trajectory?

• 1 second

• 1.5 seconds

• 2 seconds

• 3 seconds

What is the velocity of the first ball when it returns to the hand?

• 14.7 meters per second

• 7.35 meters per second

• 29.4 meters per second

• 0 meters per second

Which equation is used to calculate the velocity of the first ball?

• V = u + at

• Vy = VY0 - GT

• F = ma

• s = ut + 0.5at^2

What must be true about the Y component of the second ball's velocity?

• It must be greater than 14.7 m/s

• It must be zero

• It must be less than 14.7 m/s

• It must equal 14.7 m/s

What is the required velocity to throw the second ball at a 30-degree angle to reach the same height?

• 29.4 meters per second

• 35.0 meters per second

• 14.7 meters per second

• 21.0 meters per second

Why is it unnecessary to know the exact height reached by the balls?

• Because only the Y component of velocity matters

• Because the angle of throw is constant

• Because the X component of velocity is irrelevant

• Because the time of flight is the same