Springs don't include force due to gravity proof

The video tutorial explains why the force of gravity acting on a block connected to a spring does not appear in the final equation of motion. It is not neglected but cancels out mathematically. The tutorial covers the static deflection of a spring with a mass attached, using a free body diagram to illustrate the forces involved. It then explores the dynamic behavior of the spring system when stretched further, leading to the realization that gravity cancels out in the equation, resulting in a simple harmonic motion formula.

Why does the gravitational force not appear in the final equation of motion for a block connected to a spring?

• It cancels out mathematically.

• It is neglected because it is too small.

• It is only relevant in horizontal systems.

• It is not considered in vertical systems.

What is the significance of the equation MG = K delta in the context of a spring-mass system?

• It represents the equilibrium condition of the system.

• It determines the spring constant.

• It calculates the mass of the block.

• It describes the maximum stretch of the spring.

In the context of the spring-mass system, what does the term 'static deflection' refer to?

• The maximum acceleration of the block.

• The natural frequency of the system.

• The distance the spring stretches under a static load.

• The initial position of the spring.

What is the final equation of motion derived for the spring-mass system when considering dynamic behavior?

• MX double dot - KX = 0

• MG + K delta = 0

• MG - K delta = 0

• MX double dot + KX = 0

How does the equation of motion for a vertical spring-mass system compare to that of a horizontal one?

• The vertical system has an additional gravitational term.

• The horizontal system is more complex.

• They are completely different.

• They result in the same equation of motion.