Selection Sort Complexity

The video tutorial explains the complexity of selection sort, focusing on its O(n^2) complexity. It uses two loops, resulting in n^2 iterations. A mathematical explanation is provided, showing the series n(n-1)/2, which simplifies to n^2/2 - n/2. The video discusses best, average, and worst-case scenarios, all resulting in O(n^2) complexity. The tutorial concludes by emphasizing the importance of understanding selection sort's complexity and encourages viewers to revisit the material if needed.

What is the time complexity of selection sort due to its nested loops?

• O(n log n)

• O(n)

• O(n^2)

• O(log n)

How is the complexity of selection sort mathematically derived?

• By analyzing the number of comparisons

• By counting the number of swaps

• By measuring the execution time

• By evaluating the number of recursive calls

What is the formula used to calculate the sum of comparisons in selection sort?

• n^2 / 2 + n / 2

• n * (n - 1) / 2

• n^2 / 2 - n / 2

• n * (n + 1) / 2

In which case does selection sort have a time complexity of O(n^2)?

• Average case

• Best case

• Worst case

• All of the above

Why does selection sort have the same complexity in the best, average, and worst cases?

• Because it uses a divide and conquer approach

• Because it always sorts in ascending order

• Because it always sorts in descending order

• Because it processes one element at a time