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Crystal Lattice Structures: Density Calculation 1

Crystal Lattice Structures: Density Calculation 1

Assessment

Interactive Video

Science, Physics, Mathematics, Chemistry

University

Practice Problem

Hard

Created by

Wayground Content

FREE Resource

The video tutorial explains how to calculate the density of gadolinium, which forms a hexagonal close-packed structure. The problem involves converting the atomic radius from angstroms to centimeters and using a specific density formula. The tutorial walks through the steps of identifying known values, applying the formula, and performing calculations to find the density in grams per cubic centimeter, resulting in a final value of approximately 7.92 g/cm³.

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5 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of structure does Gadolinium form?

Body-centered cubic

Cubic close packed

Face-centered cubic

Hexagonal close packed

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the conversion factor from angstroms to centimeters?

1 angstrom = 10^-10 cm

1 angstrom = 10^-8 cm

1 angstrom = 10^-6 cm

1 angstrom = 10^-9 cm

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the molecular weight of Gadolinium used in the calculation?

157.25 grams per mole

150.25 grams per mole

160.25 grams per mole

155.25 grams per mole

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which constant is used to represent the number of atoms per mole?

6.022 x 10^23

6.022 x 10^22

6.022 x 10^24

6.022 x 10^21

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final calculated density of Gadolinium in grams per cubic centimeter?

7.92

7.82

7.72

7.62

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