Estimating Gradients and Area Under a Curve

Estimating Gradients and Area Under a Curve

Assessment

Interactive Video

Mathematics, Social Studies

11th Grade - University

Hard

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Quizizz Content

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The video tutorial explains how to estimate gradients and calculate the area under a curve. It begins by discussing the limitations of using average gradients and suggests breaking the graph into smaller zones for better accuracy. The tutorial then covers calculating exact gradients using tangents and highlights the challenges of estimating by eye. Finally, it explains how to estimate distance traveled using the area under a velocity-time graph, employing trapezium and triangle formulas.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is calculating the average gradient over a large interval not very accurate?

It requires complex calculations.

It misses out on variations within the interval.

It only works for straight lines.

It only considers the highest point on the graph.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of drawing tangents on a curve?

To find the average speed over time.

To calculate the gradient at a specific point.

To determine the total distance traveled.

To identify the highest point on the curve.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a challenge when estimating gradients using tangents?

Tangents are difficult to draw accurately by eye.

Tangents require advanced mathematical tools.

Tangents do not provide any useful information.

Tangents can only be used on straight lines.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which formula is used to calculate the area of a trapezium?

Base times height

Half base times height

Half (A+B) times height

A times B times height

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important for the shapes used in area estimation to have equal width?

To avoid using the trapezium formula.

To ensure the calculations are simpler.

To maintain consistency in the estimation.

To make the graph look symmetrical.