Solving a System Using Elimination and Subtraction

Solving a System Using Elimination and Subtraction

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

Created by

Wayground Content

FREE Resource

7 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a key condition for using substitution effectively in algebraic equations?

The variable must be a constant.

The variable must have a coefficient of 1 or -1.

The variable must be eliminated first.

The variable must have a coefficient of 2.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When using elimination, what is crucial for the coefficients of the variables?

They must be zero.

They must be different.

They must be positive.

They must be identical.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of subtracting two equations with identical coefficients?

The variable is eliminated.

The equations become identical.

The coefficients are halved.

The coefficients are doubled.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After solving for one variable using elimination, what is the next step?

Multiply the equation by 2.

Solve for the other variable using substitution.

Add the equations again.

Divide the equation by the coefficient.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is an alternative method to subtraction when solving equations?

Multiplying by 2.

Adding a constant to both sides.

Dividing by the coefficient.

Multiplying by -1 to facilitate addition.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why might one choose to multiply an equation by -1?

To make subtraction easier.

To change the variable.

To eliminate the variable.

To facilitate addition by creating opposite signs.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What must be ensured when adding equations after multiplying by -1?

Both equations have the same sign.

One equation has a positive and the other a negative sign.

The variables are constants.

Both equations are multiplied by 2.