Why is it important for a function to be continuous on a closed interval?
Apply the EVT to the square function

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Mathematics
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11th Grade - University
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Hard
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5 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
To simplify integration
To make it easier to graph
To guarantee the existence of maximum and minimum values
To ensure it has a derivative
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in identifying the maximum and minimum values of a function on a closed interval?
Calculating the derivative
Checking the endpoints
Finding the inflection points
Determining the average value
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
According to the example, what are the minimum and maximum values identified?
(1, 1) and (2, 8)
(0, 3) and (3, 0)
(1, 0) and (3, 9)
(0, 0) and (3, 9)
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does the Extreme Value Theorem ensure for a continuous function on a closed interval?
It is differentiable
It is integrable
It has both a maximum and a minimum value
It has a unique solution
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the significance of checking the graph of the function on the interval?
To find the derivative
To confirm the endpoints
To visualize the maximum and minimum points
To determine the slope
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