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How to find the x values that make a horizontal tangent implicitly

How to find the x values that make a horizontal tangent implicitly

Assessment

Interactive Video

Mathematics

11th Grade - University

Practice Problem

Hard

Created by

Wayground Content

FREE Resource

The video tutorial explains how to find horizontal tangents by differentiating an equation and solving for X values. It covers the concept of horizontal tangents, the differentiation process, and solving the equation to find the X values that produce horizontal tangents.

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7 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary goal when looking for horizontal tangents in an equation?

Finding the x and y coordinates

Finding the y-intercept

Finding the derivative of the equation

Finding the slope of the tangent

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which mathematical rule is applied when differentiating the product of two functions?

Chain Rule

Product Rule

Quotient Rule

Power Rule

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What condition must be met for a tangent to be horizontal?

dy/dx is greater than zero

dy/dx is less than zero

dy/dx is equal to zero

dy/dx is undefined

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When solving for horizontal tangents, which part of the derivative equation is set to zero?

The denominator

Neither

The numerator

Both numerator and denominator

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the next step after finding that y equals -4x for horizontal tangents?

Check for vertical tangents

Solve for y-values

Find the derivative again

Substitute into the original equation

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of substituting y = -4x into the original equation?

Finding the slope of the tangent

Finding the maximum point

Finding the x-values for horizontal tangents

Finding the y-intercepts

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the x-values where horizontal tangents occur in this problem?

x = ± sqrt(2/3)

x = ± sqrt(62/3)

x = ± sqrt(3/2)

x = ± sqrt(3/62)

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