Find the equation of a circle given the center and line tangent to the circle

Find the equation of a circle given the center and line tangent to the circle

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

Created by

Quizizz Content

FREE Resource

The video tutorial explains how to write the equation of a circle given its center and the fact that it is tangent to the X axis. It covers the standard form of a circle's equation, the concept of tangency, and how to determine the radius by understanding the distance from the center to the X axis. The tutorial uses a step-by-step approach to ensure comprehension of these geometric concepts.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the standard form of a circle's equation?

(X + H)^2 + (Y + K)^2 = R^2

(X - H)^2 + (Y - K)^2 = R^2

X^2 + Y^2 = R^2

X^2 + Y^2 = 2R

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If a circle is tangent to the X-axis, how many points does it touch the axis?

Two points

No points

One point

Three points

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does it mean for a line to be tangent to a circle?

It crosses the circle at two points

It does not touch the circle

It is parallel to the circle

It touches the circle at exactly one point

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the radius of the circle determined when it is tangent to the X-axis?

By measuring the diameter of the circle

By measuring the distance from the center to the X-axis

By measuring the distance from the center to the Y-axis

By measuring the circumference of the circle

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final equation of the circle given the center (-6, 5) and tangent to the X-axis?

(X + 6)^2 + (Y - 5)^2 = 36

(X - 6)^2 + (Y + 5)^2 = 36

(X + 6)^2 + (Y + 5)^2 = 36

(X - 6)^2 + (Y - 5)^2 = 36