GCSE Secondary Maths Age 13-17 - Algebra: Temperature - Centigrade and Fahrenheit - Explained

GCSE Secondary Maths Age 13-17 - Algebra: Temperature - Centigrade and Fahrenheit - Explained

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Quizizz Content

FREE Resource

The video tutorial explains how to convert temperatures from Fahrenheit to Celsius using a specific formula. It includes an example problem involving Mrs. Smith's home temperature to determine if it meets the minimum requirement for elderly homes. The tutorial also covers rearranging the formula to make Fahrenheit the subject, providing step-by-step guidance on the algebraic process.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula used to convert temperatures from Fahrenheit to Celsius?

C = (F + 32) * 9/5

C = (F - 32) * 9/5

C = (F + 32) * 5/9

C = (F - 32) * 5/9

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the minimum temperature in Celsius that should be maintained in an elderly person's home?

18 degrees Celsius

20 degrees Celsius

25 degrees Celsius

22 degrees Celsius

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After converting 77 degrees Fahrenheit, what is the temperature in Celsius?

27 degrees Celsius

22 degrees Celsius

25 degrees Celsius

20 degrees Celsius

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Is Mrs. Smith's home temperature higher or lower than the minimum required temperature?

Equal

Higher

Cannot be determined

Lower

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many marks were awarded for correctly substituting the value into the formula?

Two marks

One mark

Four marks

Three marks

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in rearranging the formula to make Fahrenheit the subject?

Add 32 to both sides

Multiply both sides by 9

Divide both sides by 5

Subtract 160 from both sides

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final rearranged formula to make Fahrenheit the subject?

F = (5C + 160) / 9

F = (5C - 160) / 9

F = (9C + 160) / 5

F = (9C - 160) / 5