GCSE Secondary Maths Age 13-17 - Geometry & Measures: Parallel Lines - Explained

The video tutorial explains how to find an expression for b in terms of a, given two points P and Q and a line perpendicular to PQ. It covers calculating the gradient of the perpendicular line, determining the gradient of line PQ, and using rise over run to relate gradients to coordinates. The tutorial concludes with solving for b in terms of a and discussing the marking scheme for the problem.

How can you express b in terms of a using the coordinates of points P and Q?

What steps are involved in rearranging the equation to isolate b?

What is the final expression for b in terms of a?