GCSE Secondary Maths Age 13-17 - Algebra: Recurring Decimals / Algebra - Explained

The video tutorial demonstrates how to use algebra to convert recurring decimals into fractions and solve a problem involving the multiplication of these fractions. The instructor begins by setting up the problem, converting 0.136 recurring into a fraction using algebraic techniques, and then multiplies it with 0.2 recurring. The video also covers an alternative method for converting 0.2 recurring and discusses the marking scheme for the problem. The tutorial concludes by emphasizing the mechanical nature of the problem and the importance of understanding the algebraic process.

What is the first step taken to convert nought .136363636 into a fraction?

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What two equations are formed during the conversion of nought .136363636 to a fraction?

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How is the fraction 3/22 derived from the recurring decimal nought .136363636?

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What is the equivalent fraction for nought .2 recurring, and how is it determined?

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What is the significance of isolating the recurring decimal part in the algebraic process?

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Explain how the recurring decimal part is isolated in the process.

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Describe the method used to convert nought .1 recurring into a fraction.

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