Algebra 2 - Using direct variation and proportions to find your missing value

The video tutorial explains the concept of direct variation, represented by the equation y = KX. It demonstrates how to solve a problem involving direct variation by setting up a proportion and using cross multiplication. The example given is finding the value of X when Y is 3, given that Y is 4 when X is -2. The solution involves setting up the proportion 4/-2 = 3/X, applying cross multiplication, and solving for X, which results in X = -3/2.

What is the formula for direct variation as mentioned in the text?

How can we express the relationship between Y and X when Y is 4 and X is -2?

What method is used to solve for the missing value in a proportion?

Explain the cross product method as applied in the problem.

What is the value of X when Y is 3, based on the direct variation discussed?