Circle Equations and Properties

Circle Equations and Properties

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Sophia Harris

FREE Resource

The video tutorial explains how to use algebra to describe patterns, focusing on deriving the equation of a circle centered at the origin using the Pythagorean theorem. It reviews the theorem, defines circle properties, and demonstrates how to derive and apply the circle equation to find points on the circle. Specific examples are provided to illustrate the process.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary focus of using algebra in this lesson?

To calculate the area of a triangle

To solve quadratic equations

To derive the equation of a circle

To describe the pattern of a line

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the Pythagorean theorem relate in a right triangle?

The angles and the hypotenuse

The area and the perimeter

The lengths of the legs and the hypotenuse

The radius and the diameter

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is a circle defined in terms of its points?

As a set of points equidistant from a plane

As a set of points equidistant from a triangle

As a set of points equidistant from a point

As a set of points equidistant from a line

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What equation describes every point on a circle centered at the origin?

x + y = r

x^2 + y^2 = r^2

x^2 - y^2 = r^2

x^2 + y^2 = 2r

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What must be known to describe a specific circle using its equation?

The circumference

The area

The diameter

The radius

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equation of a circle with a radius of 8 centered at the origin?

x^2 + y^2 = 32

x^2 + y^2 = 8

x^2 + y^2 = 64

x^2 + y^2 = 16

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you find the radius of a circle passing through a point (x, y)?

By using the distance formula

By applying the Pythagorean theorem

By measuring the diameter

By calculating the area

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