Gas Stoichiometry and Ideal Gas Law Explained

Gas Stoichiometry and Ideal Gas Law Explained

Assessment

Interactive Video

Chemistry, Science, Physics

9th - 12th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial covers gas stoichiometry, focusing on the ideal gas law and its application in solving stoichiometry problems. It begins with a correction of the gas constant value used throughout the video. The tutorial explains standard temperature and pressure (STP) and demonstrates how to calculate the volume of one mole of gas at STP using the ideal gas law. An example problem is presented, showing how to determine the mass of aluminum reacted with oxygen gas at STP, integrating stoichiometry and gas law concepts.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the correct value of the universal gas constant mentioned in the video?

0.08314

0.08206

0.08500

0.08000

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does STP stand for in the context of gas stoichiometry?

Standard Time and Proportion

Standard Time and Pressure

Standard Temperature and Proportion

Standard Temperature and Pressure

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the standard pressure at STP?

1 atm

1.5 atm

2 atm

0.5 atm

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

At STP, what volume does one mole of gas occupy according to the ideal gas law?

22.42 liters

20.00 liters

24.00 liters

18.00 liters

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example problem, what is the volume of oxygen gas given?

3 liters

4 liters

2 liters

1 liter

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving the example problem involving aluminum and oxygen?

Find the temperature of the reaction

Determine the number of moles of oxygen

Calculate the mass of aluminum

Measure the pressure of the gas

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many moles of oxygen are present in 2 liters of oxygen gas at STP?

0.089 moles

0.100 moles

0.050 moles

0.200 moles

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