Mastering Chemical Formulas Through Subscripts and Coefficients

Mr. Packard introduces key chemistry vocabulary, focusing on subscripts and coefficients in chemical formulas. He explains how subscripts indicate the number of atoms of an element, while coefficients show the number of molecules. The lesson includes examples like CO2 and H2O, and demonstrates using the distributive property to calculate atom counts. Students are given an assignment to practice counting atoms in chemical formulas, with advanced examples and challenge problems to reinforce learning.

What does the subscript in a chemical formula indicate?

• The type of chemical bond

• The number of molecules present

• The number of atoms of the element

• The charge of the element

In the chemical formula CO2, what does the '2' represent?

• Two molecules of carbon dioxide

• Two atoms of carbon

• Two atoms of oxygen

• Two molecules of oxygen

What is the role of a coefficient in a chemical formula?

• It represents the type of chemical reaction

• It determines the molecular weight

• It indicates the number of atoms in a molecule

• It shows the number of molecules present

How many molecules of NH3 are represented by the formula 2NH3?

• Three molecules

• Two molecules

• One molecule

• Four molecules

What is the first step in the assignment on chemical formulas?

• Counting atoms in chemical formulas

• Calculating molecular weight

• Balancing chemical equations

• Identifying chemical reactions

In the formula Cl2, how many atoms of chlorine are present?

• Three atoms

• One atom

• Two atoms

• Four atoms

How many atoms of hydrogen are in 3H2SO4?

• Two atoms

• Six atoms

• Four atoms

• Eight atoms

What is the total number of oxygen atoms in 3H2SO4?

• Eight atoms

• Sixteen atoms

• Twelve atoms

• Four atoms

In the challenge problem, how many molecules are represented by the coefficient in C6H12O6?

• One molecule

• Two molecules

• Four molecules

• Three molecules

What is the chemical formula for glucose?

• C6H12O6

• C2H5OH

• CH4

• C12H22O11