Mastering Distance-Time Graphs and Unit Conversions in Physics

Mastering Distance-Time Graphs and Unit Conversions in Physics

Assessment

Interactive Video

Physics, Mathematics, Science

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

This video tutorial explains how to draw and interpret distance-time graphs, focusing on the importance of using standard units for distance and time. It covers converting units, recognizing graph lines, and calculating speed. The tutorial also discusses acceleration and deceleration, emphasizing the need for clear calculations in exams. The video concludes with a detailed example of calculating speed in different graph sections.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the standard units for measuring distance and time in physics?

Kilometers and hours

Meters and seconds

Miles and minutes

Feet and hours

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many seconds are there in one hour?

600 seconds

1200 seconds

3600 seconds

2400 seconds

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If you have a distance of 0.5 kilometers, how many meters is that?

50 meters

5 meters

500 meters

5000 meters

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does a straight horizontal line on a distance-time graph indicate?

Steady speed

Acceleration

Deceleration

Stationary

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does a curve on a distance-time graph typically represent?

Steady speed

Acceleration or deceleration

Stationary

Constant speed

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In a distance-time graph, what does it mean if the distance remains constant while time increases?

The object is stationary

The object is decelerating

The object is accelerating

The object is moving at a steady speed

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you calculate speed from a distance-time graph?

Distance multiplied by time

Initial distance divided by final time

Final distance minus initial distance divided by final time minus initial time

Final distance multiplied by initial time

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