Titration and Concentration Calculations

Titration and Concentration Calculations

Assessment

Interactive Video

Chemistry, Mathematics, Science

10th - 12th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial covers titration calculations, focusing on an acid-base reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH). It explains how to determine the concentration of an unknown HCl solution by reaching the equivalence point with a known concentration of NaOH. The tutorial walks through the process of calculating moles of base, using stoichiometry to find moles of acid, and finally determining the concentration of the HCl solution.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the products formed when hydrochloric acid reacts with sodium hydroxide?

Sodium chloride and water

Hydrogen gas and sodium chloride

Sodium hydroxide and hydrochloric acid

Chlorine gas and water

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the equivalence point in a titration?

It is the point where the solution changes color.

It is the point where the moles of acid equal the moles of base.

It is the point where the solution reaches its maximum temperature.

It is the point where the solution becomes neutral.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you convert milliliters to liters?

Multiply by 1000

Divide by 1000

Multiply by 100

Divide by 100

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the concentration of sodium hydroxide used in the titration?

0.250 M

0.500 M

0.125 M

0.750 M

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many moles of base were required to reach the equivalence point?

0.0500 moles

0.0352 moles

0.0250 moles

0.00881 moles

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the stoichiometric ratio between hydrochloric acid and sodium hydroxide in this reaction?

2:2

1:1

2:1

1:2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you calculate the concentration of a solution?

Divide moles by volume in liters

Multiply moles by volume in liters

Subtract moles from volume in liters

Add moles to volume in liters

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