pH Calculations and Spectator Ions

pH Calculations and Spectator Ions

Assessment

Interactive Video

Chemistry, Science, Mathematics

11th - 12th Grade

Hard

Created by

Patricia Brown

FREE Resource

This video tutorial explains how to calculate the pH of salt solutions, focusing on sodium fluoride and ammonium chloride. It covers the process of identifying spectator ions, setting up reactions, and using the ICE table method. The video also provides shortcuts for calculating pH and offers additional resources for mastering chemistry concepts.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in calculating the pH of a salt solution?

Identify the solvent used

Determine the concentration of the salt

Calculate the molar mass of the salt

Cross out any spectator ions

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which ion is left after removing spectator ions from sodium fluoride?

OH-

F-

Na+

H+

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of setting up an ICE table in pH calculations?

To determine the initial concentration of the solvent

To calculate the change in concentration of reactants and products

To find the molar mass of the compound

To measure the temperature of the solution

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the KB value calculated if only the KA is given?

By multiplying KA with the concentration of the base

By dividing 1.0 x 10^-14 by the KA

By subtracting KA from 1.0 x 10^-14

By adding KA to the concentration of the acid

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the pH of a solution if the pOH is 5.41?

14.00

5.41

7.00

8.59

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in calculating the pH of a weak acid solution?

Calculate the molar mass of the acid

Cross out any spectator ions

Determine the concentration of the acid

Identify the solvent used

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which ion is left after removing spectator ions from ammonium chloride?

Cl-

NH4+

H+

OH-

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