Positron Emission and Radioactive Decay

Positron Emission and Radioactive Decay

Assessment

Interactive Video

Physics, Chemistry, Science

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial explains how to balance equations for radioactive decay, focusing on positron emission. It describes the process where a proton breaks into a positron and a neutron, affecting the atomic and mass numbers. The tutorial guides viewers through determining the new atomic number and chemical symbol, using the periodic table to identify the element as oxygen. The mass number remains unchanged due to the neutron's presence. The final balanced equation is presented, illustrating the transformation from fluorine-18 to oxygen-18.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of radioactive decay does Fluorine-18 undergo in the given problem?

Gamma decay

Alpha decay

Beta decay

Positron emission

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

During positron emission, a proton transforms into which of the following?

An alpha particle

A positron and a neutron

An electron and a neutron

A neutron and a gamma ray

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the context of radioactive decay, what is a positron?

A neutral particle

A positively charged electron

A negatively charged particle

A heavy particle

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the role of the neutron in the nucleus after positron emission?

It transforms into a proton

It transforms into an electron

It remains in the nucleus

It is ejected from the nucleus

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After positron emission, what is the new atomic number of the element?

8

7

9

10

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which element is represented by the atomic number 8?

Nitrogen

Neon

Oxygen

Fluorine

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the mass number when a proton is lost during positron emission?

It increases by one

It decreases by one

It remains the same

It doubles

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