Train Velocity and Acceleration Problems

The video tutorial discusses a problem from class 9 science, chapter 7 on motion. It involves a train starting from rest and reaching a velocity of 72 km/h in 5 minutes. The tutorial is divided into two main parts: calculating the acceleration and the distance traveled by the train. The instructor explains the conversion of units and uses formulas to find the acceleration and distance. The acceleration is found to be 1/15 m/s², and the distance traveled is 3 km. The video concludes with a summary of the results.

What is the initial velocity of the train?

• 72 km/h

• 20 m/s

• 5 m/s

• 0 m/s

How long does it take for the train to reach a velocity of 72 km/h?

• 10 minutes

• 7 minutes

• 3 minutes

• 5 minutes

What is the final velocity of the train in meters per second?

• 72 m/s

• 20 m/s

• 18 m/s

• 25 m/s

How do you convert km/h to m/s?

• Multiply by 5/18

• Multiply by 18/5

• Multiply by 1000

• Multiply by 60

What is the formula used to calculate acceleration?

• Force / Mass

• (Final velocity - Initial velocity) / Time

• Mass x Acceleration

• Distance / Time

What is the calculated acceleration of the train?

• 2 m/s²

• 3 m/s²

• 1/15 m/s²

• 1/10 m/s²

Which formula is used to calculate the distance traveled by the train?

• s = ut + 1/2at²

• 2as = v² - u²

• s = vt

• v = u + at

What is the distance traveled by the train in meters?

• 2000 m

• 1500 m

• 3000 m

• 1000 m

How is the distance in meters converted to kilometers?

• Subtract 1000

• Divide by 1000

• Multiply by 1000

• Add 1000

What is the final distance traveled by the train in kilometers?

• 4 km

• 3 km

• 2 km

• 1 km