Dilution and Molarity Concepts

Dilution and Molarity Concepts

Assessment

Interactive Video

Chemistry, Mathematics, Science

9th - 12th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial explains an example from slide 76 of chapter 12, focusing on using the solution dilution equation with molarity. The problem involves finding the molarity of a solution when 75 milliliters of a 4 molar KCl solution is diluted to 500 milliliters. The tutorial guides through identifying the variables C1, V1, C2, and V2, and solving the equation to find the final molarity, which is approximately 0.6 molar.

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8 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main focus of the example discussed in the video?

Determining the density of a solution

Calculating the mass of a solution

Using the solution dilution equation with molarity

Using the solution dilution equation with percent concentration

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial concentration of the KCl solution in the problem?

5 molar

4 molar

3 molar

2 molar

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial volume of the KCl solution before dilution?

125 milliliters

100 milliliters

75 milliliters

50 milliliters

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

To what volume is the KCl solution diluted?

500 milliliters

450 milliliters

550 milliliters

400 milliliters

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which variable represents the unknown concentration in the dilution equation?

C1

V1

V2

C2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula used to calculate the unknown molarity in the dilution equation?

C1 + V1 = C2 + V2

C1 / V1 = C2 / V2

C1 - V1 = C2 - V2

C1 * V1 = C2 * V2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the calculated molarity of the diluted KCl solution?

0.7 molar

0.5 molar

0.4 molar

0.6 molar

8.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What operation is performed to isolate C2 in the dilution equation?

Multiplying both sides by 500 milliliters

Dividing both sides by 500 milliliters

Subtracting 500 milliliters from both sides

Adding 500 milliliters to both sides