Trigonometry and Vector Components

Trigonometry and Vector Components

Assessment

Interactive Video

Mathematics, Physics, Science

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial explains how to solve a problem involving Bernard walking 50 meters at an angle of 48 degrees south of west. It covers the calculation of horizontal and vertical components using trigonometric functions. The angle Theta is determined by adding 180 degrees to 48 degrees, resulting in 228 degrees. The horizontal component is calculated using the cosine of 228 degrees, yielding -11.62 meters, while the vertical component is found using the sine of 228 degrees, resulting in 48.63 meters.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial distance Bernard walks?

90 meters

70 meters

30 meters

50 meters

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In which direction does Bernard start his walk?

South of West

North of East

West of South

East of North

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the angle of Bernard's walk relative to the east?

180 degrees

228 degrees

90 degrees

48 degrees

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the angle of 228 degrees derived?

By subtracting 90 degrees from 180 degrees

By adding 180 degrees to 48 degrees

By subtracting 48 degrees from 180 degrees

By adding 90 degrees to 48 degrees

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which trigonometric function is used to find the horizontal component?

Secant

Sine

Tangent

Cosine

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of the horizontal component of Bernard's walk?

11.62 meters

-11.62 meters

48.63 meters

-48.63 meters

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which trigonometric function is used to find the vertical component?

Cotangent

Tangent

Cosine

Sine

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