Heat Energy and Temperature Calculations

Heat Energy and Temperature Calculations

Assessment

Interactive Video

Physics, Chemistry, Science

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial explains how to calculate the amount of heat required to raise the temperature of a 75g iron block from 25°C to its melting point of 1535°C. It covers the use of the formula Q = m * L * delta T, where Q is the heat energy, m is the mass, L is the specific heat, and delta T is the change in temperature. The tutorial demonstrates the calculation of delta T, solving for Q in joules, and converting the result to calories. The video concludes with a call to action for viewers to engage with the channel.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial temperature of the iron block in the problem?

75°C

135°C

25°C

1535°C

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which formula is used to calculate the heat energy required to change the temperature of a substance?

Q = m * a * ΔT

Q = m * c * ΔT

Q = m * v * ΔT

Q = m * s * ΔT

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the symbol 'ΔT' represent in the formula Q = m * s * ΔT?

Total temperature

Initial temperature

Change in temperature

Final temperature

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the change in temperature (ΔT) calculated?

Final temp - Initial temp

Initial temp - Final temp

Sum of initial and final temp

Average of initial and final temp

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the specific heat capacity of iron used in the problem?

0.700 J/g°C

0.500 J/g°C

0.600 J/g°C

0.449 J/g°C

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the calculated heat energy in joules required to raise the temperature of the iron block?

508 J

50,800 J

500,800 J

5,080 J

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the conversion factor from joules to calories?

1 cal = 4.184 J

1 cal = 3.184 J

1 cal = 5.184 J

1 cal = 2.184 J

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