Effects of Dilution on HCl Solutions

Effects of Dilution on HCl Solutions

Assessment

Interactive Video

Chemistry, Science, Mathematics

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial explores the effect of diluting a strong acid, HCL, on its pH level. Starting with an HCL solution at pH 3, the video guides viewers through the process of diluting it by a factor of 10 and predicting the new pH. It presents three possible outcomes and explains each one. The tutorial concludes with a detailed calculation, showing that the pH increases from 3 to 4 due to the dilution.

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8 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the pH of a strong acid like HCl when it is diluted by a factor of 10?

The pH increases.

The pH becomes neutral.

The pH remains the same.

The pH decreases.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is a possible explanation for the pH change when a strong acid is diluted?

Dilution makes the solution more acidic.

Dilution increases the H3O+ concentration.

Dilution has no effect on the solution.

Dilution decreases the H3O+ concentration.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the effect of dilution on the H3O+ concentration in a strong acid solution?

It increases by a factor of 10.

It decreases by a factor of 10.

It doubles.

It remains constant.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do strong acids like HCl behave in solution?

They do not dissociate.

They form a precipitate.

They completely dissociate.

They partially dissociate.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial H3O+ concentration of an HCl solution at pH 3?

10^-2 M

10^-4 M

10^-3 M

10^-1 M

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After diluting an HCl solution by a factor of 10, what is the new H3O+ concentration?

10^-5 M

10^-3 M

10^-2 M

10^-4 M

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the new pH of the HCl solution after dilution?

2

3

4

5

8.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the correct calculation for the new pH after dilution?

pH = 4 + log(10)

pH = 3 + log(10)

pH = 3 - log(10)

pH = 4 - log(10)