Balancing Redox Reactions and Oxidation States

Balancing Redox Reactions and Oxidation States

Assessment

Interactive Video

Chemistry, Science, Other

9th - 12th Grade

Hard

Created by

Patricia Brown

FREE Resource

This video tutorial focuses on balancing redox reactions using the oxidation number method. It begins with an introduction to redox reactions and the two methods for balancing them: the half-reaction method and the oxidation number method. The video then provides a detailed step-by-step guide on using the oxidation number method, followed by two examples. The first example involves balancing a reaction between permanganate and bromide ions in a basic medium, while the second example balances a reaction between nitric acid and arsenous acid in a neutral medium. The tutorial concludes with a call to action to subscribe to the channel.

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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary focus of this lecture on balancing redox reactions?

Neither method

Both methods equally

Half-reaction method

Oxidation number method

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which step involves determining the oxidation number of each atom in the reaction?

Step 1

Step 3

Step 4

Step 2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What should be added to balance charges in a reaction occurring in a basic medium?

Electrons

Water molecules

OH- ions

H+ ions

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example involving permanganate and bromide ions, what is the change in oxidation number for manganese?

-6

+3

-3

+6

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many OH- ions are added to balance the charges in the permanganate and bromide reaction?

4

1

2

3

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the second example, what is the change in oxidation number for nitrogen?

+2

-2

-3

+3

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many water molecules are added to balance the oxygen atoms in the nitric acid and arsenous acid reaction?

Two

Three

One

None

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