Toy Car Motion and Displacement Concepts

Toy Car Motion and Displacement Concepts

Assessment

Interactive Video

Physics, Mathematics

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial explains the motion of a toy car on a track, focusing on its velocity and direction changes when it hits a bumper. The car travels at 10 m/s for 10 seconds, then reverses at 6 m/s for another 10 seconds. The tutorial covers the concepts of distance and displacement, highlighting that distance is the total path traveled, while displacement is the change in position. The video uses graphs and calculations to illustrate these concepts, emphasizing the vector nature of velocity and displacement.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial speed of the toy car before it hits the bumper?

5 meters per second

20 meters per second

15 meters per second

10 meters per second

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After hitting the bumper, in which direction does the toy car travel?

Upwards

To the right

To the left

Downwards

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the speed of the toy car after it changes direction?

8 meters per second

10 meters per second

4 meters per second

6 meters per second

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the total distance traveled by the toy car calculated?

By adding the areas under the velocity-time graph

By subtracting the areas under the velocity-time graph

By dividing the areas under the velocity-time graph

By multiplying the areas under the velocity-time graph

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total distance traveled by the toy car?

120 meters

140 meters

180 meters

160 meters

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is displacement in the context of the toy car's motion?

The total distance traveled

The change in position

The speed of the car

The time taken for the journey

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is displacement calculated from the velocity-time graph?

By dividing the areas

By multiplying the areas

By subtracting the negative area from the positive area

By adding all areas

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