Graham's Law and Gas Effusion

Graham's Law and Gas Effusion

Assessment

Interactive Video

Chemistry, Physics, Science

11th - 12th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial explains how to solve a problem using Graham's Law of Effusion. It begins with an introduction to the problem, followed by a discussion on the importance of understanding molar mass. The instructor then sets up and rearranges the equation needed to solve the problem, emphasizing the need to correctly identify the molar masses of helium and oxygen. Finally, the video demonstrates the calculation process to find the rate of effusion of oxygen molecules, providing a step-by-step guide to ensure understanding.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the given rate of helium effusion in the problem?

2.76 x 10^-4 moles per second

3.00 x 10^-4 moles per second

1.50 x 10^-4 moles per second

2.00 x 10^-4 moles per second

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary concept needed to solve the problem?

Boyle's Law

Charles's Law

Avogadro's Law

Graham's Law of Effusion

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to remember that oxygen is diatomic?

To measure the pressure of oxygen

To find the density of oxygen

To determine the volume of oxygen

To calculate the correct molar mass

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the molar mass of helium used in the calculation?

4.002 grams per mole

16.00 grams per mole

32.00 grams per mole

8.00 grams per mole

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the square root symbol represented in the equation?

As a fraction

As a logarithm

As a power of one-half

As a cube root

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What operation is performed to isolate the rate of oxygen effusion?

Multiplication

Addition

Subtraction

Division

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final calculated rate of oxygen effusion?

9.76 x 10^-5 moles per second

8.00 x 10^-5 moles per second

7.50 x 10^-5 moles per second

6.25 x 10^-5 moles per second

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