
Circuit Analysis and Resistance Concepts

Interactive Video
•
Physics, Science, Computers
•
9th - 12th Grade
•
Hard

Patricia Brown
FREE Resource
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the configuration of the three light bulbs in the circuit setup on Tinkercad?
Two bulbs in series, one in parallel
All bulbs in parallel
Two bulbs in parallel, one in series
All bulbs in series
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What happens to the circuit if one bulb in the series pathway is removed?
The parallel bulb turns off
All bulbs turn off
Only the removed bulb turns off
The circuit continues to function normally
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why is it beneficial to use Tinkercad's power supply for measuring current?
It is easier to use than a multimeter
It can measure voltage and resistance simultaneously
It provides precise current measurements
It is cheaper than a multimeter
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the total current in the circuit measured using a multimeter?
By connecting it in parallel with the power supply
By connecting it in series with the power supply
By connecting it in series with the bulbs
By connecting it in parallel with the bulbs
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the purpose of using multiple multimeters in the circuit setup?
To measure temperature changes
To increase the circuit's resistance
To decrease the circuit's voltage
To measure current and voltage in different pathways
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does Kirchhoff's voltage law state about voltage in a series circuit?
Voltage is zero across all components
Total voltage is the sum of individual voltage drops
Voltage is divided equally among components
Voltage is the same across all components
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the total resistance in a parallel circuit calculated?
By multiplying the resistances of all pathways
By subtracting the smallest resistance from the largest
By adding the resistances of all pathways
By taking the reciprocal of the sum of reciprocals of individual resistances
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