Image Formation in Mirrors

Image Formation in Mirrors

Assessment

Interactive Video

Mathematics, Physics, Science

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial explains how to solve a problem involving a concave mirror. It begins by introducing the problem, which involves finding the image distance and height of an object placed in front of a concave mirror. The tutorial walks through the calculations step-by-step, using the mirror equation to find the image distance and height. It also explains the significance of a negative image distance, indicating a virtual image. The video concludes with a discussion on sign conventions for concave and convex mirrors.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the focal length of the concave mirror used in the problem?

12 cm

10 cm

8 cm

6 cm

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How tall is the object placed in front of the mirror?

2 cm

4 cm

5 cm

3 cm

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What formula is used to calculate the image distance in a concave mirror?

F = Do - Di

F = Do + Di

1/F = 1/Do + 1/Di

1/F = Do * Di

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does a negative image distance indicate about the image?

The image is virtual and behind the mirror.

The image is larger than the object.

The image is smaller than the object.

The image is real and in front of the mirror.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of image is formed when the image distance is negative?

Real image

Virtual image

Inverted image

Magnified image

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which formula is used to calculate the image height?

Hi/Ho = Di/Do

Hi/Ho = -Di/Do

Hi/Ho = Do/Di

Hi/Ho = -Do/Di

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does a positive image height indicate about the image orientation?

The image is inverted.

The image is reduced.

The image is right side up.

The image is magnified.

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