Circle Geometry Concepts and Applications

Circle Geometry Concepts and Applications

Assessment

Interactive Video

Mathematics

7th - 8th Grade

Hard

Created by

Thomas White

FREE Resource

This video tutorial covers the concept of finding the area of a circle, building on the previous lesson about circumference. It explains key vocabulary such as radius and diameter, introduces the concept of pi, and demonstrates how to derive the formula for the area of a circle. Practical examples, including a biscuit and a circular garden, are used to apply the formula and reinforce understanding. The video also emphasizes the importance of order of operations in calculations.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the relationship between the diameter and the radius of a circle?

The diameter is three times the radius.

The diameter is twice the radius.

The diameter is equal to the radius.

The diameter is half the radius.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is the number pi considered an irrational number?

It can be expressed as a simple fraction.

Its decimal representation repeats.

Its decimal representation is non-repeating and infinite.

It is less than 3.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the approximate value of pi used in 7th-grade math?

3.14

3.14159

3.142

3.1416

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the area of a circle calculated?

Area = pi * radius

Area = pi * diameter

Area = 2 * pi * radius

Area = pi * radius squared

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the hands-on activity, what shape is formed by rearranging the circle's wedges?

A parallelogram

A triangle

A square

A rectangle

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If a biscuit cutter has a radius of 4 cm, what is the area of the biscuit?

50.24 cm²

25.12 cm²

12.56 cm²

16 cm²

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What should you do if you are given the diameter and need to find the radius?

Subtract 2 from the diameter

Square the diameter

Divide the diameter by 2

Multiply the diameter by 2

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