Unit Rates and Measurement Comparisons

Unit Rates and Measurement Comparisons

Assessment

Interactive Video

Mathematics

6th - 7th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial covers lesson 2-2 on determining unit rates with ratios of fractions. It includes activities comparing plant growth, cupcake prices, cycling speed, lawn mowing times, and distance calculations. The lesson emphasizes the importance of unit rates and conversions for solving real-world problems. Students are guided through each activity with step-by-step instructions and encouraged to practice using equations.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to convert units when comparing two quantities?

To avoid using calculators

To confuse the students

To ensure a fair comparison

To make the numbers look bigger

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the unit rate for the bakery's cupcakes?

83 cents per cupcake

10 cupcakes for $12

70 cents per cupcake

12 cupcakes for $10

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which store offers a better deal on cupcakes?

The bakery with 83 cents per cupcake

The supermarket with 70 cents per cupcake

Both stores offer the same deal

Neither store offers a good deal

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Did Sergio achieve his target cycling speed?

No, he didn't cycle at all

Yes, he matched it exactly

No, he was below it

Yes, he exceeded it

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many square feet does Bronwyn mow in one hour?

36,000 square feet

18,000 square feet

15,000 square feet

12,000 square feet

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving a problem involving exponents and speed comparison?

Choose the power and put the fit

Directly calculate the speed

Submit the work without solving

Use a calculator to find the answer

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you find the equivalent ratio when calculating distances?

By subtracting the smaller distance from the larger one

By using the multiplicative inverse

By dividing the total distance by the number of parts

By adding the distances

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