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Equilibrium Constants and Concentrations

Equilibrium Constants and Concentrations

Assessment

Interactive Video

Chemistry

11th - 12th Grade

Practice Problem

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial explains how to organize chemical reaction data using a table, starting with the reaction equation to understand mole ratios. It covers calculating initial moles and concentrations, determining moles at equilibrium, and using mole ratios to find the moles of reactants and products. Finally, it demonstrates calculating the equilibrium constant KC, emphasizing the importance of converting moles to concentrations and understanding the units involved.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the mole ratio of carbon-carbon double bonds to hydrogen chloride in the reaction?

1:1

2:1

1:3

1:2

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial concentration of chloroalkane in the reaction?

0 moles

0.5 moles

0.135 moles

0.270 moles

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the concentration of alkene at equilibrium calculated?

By dividing initial moles by volume

By adding initial moles

By subtracting reacted moles from initial moles

By multiplying initial moles by volume

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the mole ratio of reactants to products in this equilibrium reaction?

2:1:1

1:1:1

1:2:1

1:1:2

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many moles of chloroalkane are produced at equilibrium?

0.270 moles

0.179 moles

0.135 moles

0.5 moles

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the equilibrium constant (KC) represent in this reaction?

The ratio of initial concentrations

The ratio of product concentration to reactant concentrations at equilibrium

The total moles of products

The total moles of reactants

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you convert moles to equilibrium concentrations?

By subtracting the volume

By adding the volume

By dividing by the volume

By multiplying by the volume

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