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Myopia and Lens Power Concepts

Myopia and Lens Power Concepts

Assessment

Interactive Video

Physics

9th - 10th Grade

Practice Problem

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial explains the problem of myopia, where the far point of a myopic person is 80 cm in front of the eye. It discusses the use of a concave lens to correct this vision defect by focusing the image correctly on the retina. The tutorial covers the lens formula, 1/f = 1/v - 1/u, and demonstrates how to calculate the power of the lens needed for correction. The power is determined to be -1.25 diopters, indicating the use of a concave lens to address the myopia issue.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the far point of a myopic person as mentioned in the video?

120 cm

60 cm

100 cm

80 cm

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of lens is used to correct myopia?

Concave lens

Convex lens

Cylindrical lens

Bifocal lens

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula for calculating the power of a lens?

P = 1/f (in meters)

P = f/1 (in meters)

P = f/1 (in centimeters)

P = 1/f (in centimeters)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the lens formula 1/f = 1/v - 1/u, what does 'u' represent?

Lens power

Object distance

Focal length

Image distance

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the object distance 'u' considered in the video for myopia correction?

80 cm

100 cm

50 cm

Infinity

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the image distance 'v' given in the video for myopia correction?

60 cm

120 cm

100 cm

80 cm

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of 1/f in meters after conversion from centimeters?

-0.5

-1.0

-0.8

-1.25

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