Projectile Motion Concepts and Calculations

Mr. Ellis explains zero launch angle projectiles, focusing on their horizontal and vertical motion independence. He demonstrates how to calculate the distance and velocity of a projectile launched horizontally from a height, using Victoria Falls as an example. The video covers the necessary equations and assumptions, emphasizing the separation of horizontal and vertical components to solve the problem.

What is a zero launch angle projectile?

• An object launched with no initial velocity

• An object launched at a 45-degree angle

• An object launched with a horizontal velocity

• An object launched vertically upwards

What assumption is made about the horizontal and vertical motions of a projectile?

• They are both affected by air resistance

• They have the same velocity

• They are independent of each other

• They are dependent on each other

What is the initial vertical velocity of a projectile launched horizontally?

• 0 m/s

• 3.6 m/s

• Depends on the height of the launch

• 9.8 m/s

How is the time of flight calculated for a projectile launched horizontally?

• Using the initial launch angle

• Using the horizontal velocity

• Using the mass of the projectile

• Using the vertical motion equations

What is the horizontal distance traveled by the projectile in the example problem?

• 20.3 meters

• 25.7 meters

• 10.5 meters

• 16.9 meters

What is the final horizontal velocity of the projectile?

• 9.8 m/s

• 46.0 m/s

• 3.6 m/s

• 0 m/s

How is the final vertical velocity of the projectile calculated?

• Using the initial horizontal velocity

• Using the time of flight and acceleration due to gravity

• Using the initial launch angle

• Using the horizontal distance traveled

What is the final vertical velocity of the projectile in the example problem?

• 46.0 m/s

• 3.6 m/s

• 50.0 m/s

• 9.8 m/s

How is the overall final velocity of the projectile determined?

• By using the Pythagorean theorem

• By multiplying the horizontal and vertical velocities

• By adding the horizontal and vertical velocities

• By subtracting the vertical velocity from the horizontal velocity

What is the final speed of the projectile at the base of the cliff?

• 46.14 m/s

• 46.0 m/s

• 50.0 m/s

• 3.6 m/s