Colligative Properties and Solutions

Colligative Properties and Solutions

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Hard

Created by

Patricia Brown

FREE Resource

Dr. Manus discusses colligative properties, focusing on the effects of solutes on the freezing and boiling points of solutions. The video explains the heating curve, interactions between solute and solvent particles, and how these interactions affect temperature changes. Two example problems are solved to illustrate the calculation of freezing and boiling points using molality and the van't Hoff factor. The video concludes with a brief mention of advanced concepts and encourages students to engage with the material.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary focus of colligative properties?

Chemical reactions in solutions

Properties of solutes

Interactions between solute and solvent particles

Properties of pure solvents

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How does the addition of a solute affect the freezing point of a solution?

It makes the freezing point equal to the boiling point

It raises the freezing point

It lowers the freezing point

It has no effect on the freezing point

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the boiling point of a solution when a solute is added?

It decreases

It increases

It becomes zero

It remains the same

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which factor is used to calculate the change in freezing and boiling points?

Molarity

Density

Molality

Volume

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the van't Hoff factor primarily concerned with?

The temperature of the solution

The mass of the solvent

The number of solute particles in a solution

The volume of the solution

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example problem, what is the van't Hoff factor for calcium chloride?

3

1

4

2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the freezing point change calculated in the example problem?

14.9 degrees C

0 degrees C

-14.9 degrees C

-0.5 degrees C

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