
Vertical Asymptotes in Trigonometric Functions

Interactive Video
•
Mathematics
•
9th - 10th Grade
•
Hard

Patricia Brown
FREE Resource
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the initial problem discussed in the video involving tangent of PI X?
Calculating the value of X
Finding the value of sine
Understanding the concept of cosine
Determining the vertical asymptotes
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in finding vertical asymptotes for a trigonometric function?
Set the numerator to zero
Set the denominator to zero
Multiply by PI
Divide by the reciprocal of PI
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
When is the cosine of PI X equal to zero?
When X equals 2 PI
When X equals PI over 2 plus K PI
When X equals PI
When X equals zero
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the logical reasoning behind setting the denominator to zero?
To simplify the equation
To find the maximum value
To calculate the minimum value
To determine when the function is undefined
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How can the process of finding vertical asymptotes be simplified?
By ignoring the numerator
By focusing on the denominator
By dividing by the reciprocal of PI
By multiplying by PI
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the final step in solving for X in the equation PI X equals PI over 2 plus K PI?
Multiply by the reciprocal of PI
Add K to both sides
Multiply by PI
Divide by PI
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why is it important to state that K is an integer in the final solution?
To simplify the equation
To define the periodicity of the function
To ensure the solution is valid
To specify the range of X
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