

Empirical and Molecular Formulas
Interactive Video
•
Chemistry
•
9th - 10th Grade
•
Practice Problem
•
Hard
Patricia Brown
FREE Resource
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the primary purpose of combustionary analysis in the context of glucose?
To measure the temperature of glucose
To calculate the density of glucose
To find the elemental composition of glucose
To determine the color of glucose
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
If you have a 100 gram sample of glucose, how many grams of carbon does it contain based on the given mass percentages?
39.99 grams
12 grams
6.72 grams
53.2 grams
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you calculate the number of moles of an element in a sample?
By multiplying the mass by the molar mass
By dividing the mass by the atomic number
By multiplying the mass by the atomic number
By dividing the mass by the molar mass
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the empirical formula of glucose based on the given calculations?
C2H4O2
CHO
CH2O
C6H12O6
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the relationship between the molecular formula and the empirical formula of a compound?
The molecular formula is unrelated to the empirical formula
The molecular formula is the same as the empirical formula
The molecular formula is a multiple of the empirical formula
The molecular formula is always half of the empirical formula
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Given the molar mass of glucose is 180, what is the molar mass of its empirical formula CH2O?
90
60
30
180
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you determine the value of 'n' in the relationship between molecular and empirical formulas?
By adding the molar masses of the empirical and molecular formulas
By subtracting the molar mass of the empirical formula from the molecular formula
By dividing the molar mass of the molecular formula by the molar mass of the empirical formula
By multiplying the molar mass of the empirical formula by the molecular formula
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