Mole Calculations and Solution Concentration

Mole Calculations and Solution Concentration

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial covers colligative properties, focusing on solution concentration. It explains how to calculate the percent by mass of sodium acetate in a solution and the mole fraction of water. The tutorial provides step-by-step instructions and clarifies the importance of adding solute mass to the total solution mass. The lesson concludes with a summary of the calculations and concepts discussed.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main focus of the lesson introduced in the video?

Chemical reactions

Solution concentration and colligative properties

Periodic table elements

Atomic structure

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the percent by mass of a solute in a solution calculated?

G of solvent / G of solute * 100

G of solution / G of solute * 100

G of solute / G of solvent * 100

G of solute / G of solution * 100

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the percent by mass of sodium acetate in the solution?

7.36%

5.36%

8.36%

6.36%

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the next concept introduced after calculating percent by mass?

Mole fraction

Molarity

Normality

Molality

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the molar mass of water used in the mole fraction calculation?

18.02 g/mol

20.02 g/mol

16.02 g/mol

22.02 g/mol

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many moles of water are calculated in the solution?

90.6 moles

91.6 moles

93.6 moles

92.6 moles

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the molar mass of sodium acetate used in the calculation?

82.02 g/mol

84.02 g/mol

80.02 g/mol

86.02 g/mol

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